1. Ten years ago, P was half of Q in age. If the ratio of their present ages is 3:4, what will be the total of their present ages?
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A. 45
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B. 40
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C. 35
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D. 30
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Answer : Option C
Explanation :
Let the present age of P and Q be 3x and 4x respectively.
Ten years ago, P was half of Q in age
=> (3x – 10) = ½ (4x – 10)
=> 6x – 20 = 4x – 10
=> 2x = 10
=> x = 5
total of their present ages = 3x + 4x = 7x = 7 × 5 = 35
Ten years ago, P was half of Q in age
=> (3x – 10) = ½ (4x – 10)
=> 6x – 20 = 4x – 10
=> 2x = 10
=> x = 5
total of their present ages = 3x + 4x = 7x = 7 × 5 = 35
2. Father is aged three times more than his son Sunil. After 8 years, he would be two and a half times of Sunil's age. After further 8 years, how many times would he be of Sunil's age?
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A. 4 times
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B. 4 times
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C. 2 times
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D. 3 times
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Answer : Option C
Explanation :
Assume that Sunil's present age = x.
Then father's present age = 3x + x = 4x
After 8 years, fathers age = 2 ½ times of Sunils' age
=> (4x+8) = 2 ½ × (x+8)
=> 4x + 8 = (5/2) ×(x + 8)
=> 8x + 16 = 5x+ 40
=> 3x = 40-16 = 24
=> x = 24/3 = 8
After further 8 years,
Sunil's age = x + 8+ 8 = 8+8+8 = 24
Father's age = 4x + 8 + 8 = 4 × 8 + 8 + 8 = 48
Father's age/Sunil's age = 48/24 = 2
Then father's present age = 3x + x = 4x
After 8 years, fathers age = 2 ½ times of Sunils' age
=> (4x+8) = 2 ½ × (x+8)
=> 4x + 8 = (5/2) ×(x + 8)
=> 8x + 16 = 5x+ 40
=> 3x = 40-16 = 24
=> x = 24/3 = 8
After further 8 years,
Sunil's age = x + 8+ 8 = 8+8+8 = 24
Father's age = 4x + 8 + 8 = 4 × 8 + 8 + 8 = 48
Father's age/Sunil's age = 48/24 = 2
3. A man's age is 125% of what it was 10 years ago, but 83 1/3 % of what it will be after ten 10 years. What is his present age?
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A. 70
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B. 60
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C. 50
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D. 40
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Answer : Option C
Explanation :
Let the age before 10 years = x
Then 125x/100 = x + 10
=>125x = 100x + 1000
=> x = 1000/25 = 40
Present age = x + 10 = 40 +10 = 50
Then 125x/100 = x + 10
=>125x = 100x + 1000
=> x = 1000/25 = 40
Present age = x + 10 = 40 +10 = 50
4. A man is 24 years older than his son. In two years, his age will be twice the age of his son. What is the present age of his son?
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A. 23 years
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B. 22 years
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C. 21 years
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D. 20 years
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Answer : Option B
Explanation :
Let the present age of the son = x years
Then present age the man = (x+24) years
Given that in 2 years, man's age will be twice the age of his son
=> (x+24) +2 = 2(x+2)
=> x = 22
Then present age the man = (x+24) years
Given that in 2 years, man's age will be twice the age of his son
=> (x+24) +2 = 2(x+2)
=> x = 22
5. Present ages of Kiran and Syam are in the ratio of 5 : 4 respectively. Three years hence, the ratio of their ages will become 11 : 9 respectively. What is Syam's present age in years?
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A. 28
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B. 27
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C. 26
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D. 24
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Answer : Option D
Explanation :
Ratio of the present age of Kiran and Syam = 5 : 4
=> Let the present age of Kiran = 5x
Present age of Syam = 4x
After 3 years, ratio of their ages = 11:9
=> (5x + 3) : (4x + 3) = 11 : 9
=> (5x+3) / (4x+3) = 11/9
=> 9(5x + 3) = 11(4x + 3)
=> 45x + 27 = 44x + 33
=> x = 33-27 =6
Syam's present age = 4x = 4×6 = 24
=> Let the present age of Kiran = 5x
Present age of Syam = 4x
After 3 years, ratio of their ages = 11:9
=> (5x + 3) : (4x + 3) = 11 : 9
=> (5x+3) / (4x+3) = 11/9
=> 9(5x + 3) = 11(4x + 3)
=> 45x + 27 = 44x + 33
=> x = 33-27 =6
Syam's present age = 4x = 4×6 = 24
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