SBI ASSOCIATE CLERK TEST SERIES

Directions (Q. 1-5): Following graph shows the ratio of expenditure to income of two companies A and B during the period of 2001 to 2007 - 

1. If the expenditure of Company A in 2004 is Rs 36 lakhs, then what is its income in that year?
1) 42 lakhs
2) 48 lakhs
3) 54 lakhs
4) 60 lakhs
5) 75 lakhs


2. If the income of Company A in 2002 and expenditure of Company B in the same year is equal to Rs 60 lakhs then what is the difference between their net profit in 2002?
1) 6 lakhs
2) 8 lakhs
3) 10 lakhs
4) 12 lakhs
5) None of these

3. If the income of Company A in 2001 and income of Company B in 2005 is Rs 50 lakhs and Rs 80 lakhs respectively then the profit gained by Company A in 2001 is how much percent more than that of the profit gained by Company B in 2005?
1) 62.5%
2) 67.5%
3) 82.5%
4) 87.5%
5) 75%

4. Ratio of expenditure to income of Company B in 2004 is how much percent more than that of ratio of expenditure to income of Company A in 2005?
1) 10%
2) 20%
3) 30%
4) 40%
5) 50%

5. If income of Company A in 2006 is Rs 75 lakhs then what is the expenditure of Company B in the same year?
1) 60 lakhs
2) 75 lakhs
3) 90 lakhs
4) 87.5 lakhs
5) None of these

Time and Work

1. P is able to do a piece of work in 15 days and Q can do the same work in 20 days. If they can work together for 4 days, what is the fraction of work left?
A. 8/15	B. 7/15
C. 11/15	D. 2/11

Answer : Option A

Explanation :

Amount of work P can do in 1 day = 1/15

Amount of work Q can do in 1 day = 1/20

Amount of work P and Q can do in 1 day = 1/15 + 1/20 = 7/60

Amount of work P and Q can together do in 4 days = 4 × (7/60) = 7/15

Fraction of work left = 1 – 7/15= 8/15

2. P can lay railway track between two stations in 16 days. Q can do the same job in 12 days. With the help of R, they completes the job in 4 days. How much days does it take for R alone to complete the work?
A. 9(3/5) days	B. 9(1/5) days
C. 9(2/5) days	D. 10 days

Answer : Option A

Explanation :

Amount of work P can do in 1 day = 1/16

Amount of work Q can do in 1 day = 1/12

Amount of work P, Q and R can together do in 1 day = 1/4

Amount of work R can do in 1 day = 1/4 - (1/16 + 1/12) = 3/16 – 1/12 = 5/48

=> Hence R can do the job on 48/5 days = 9 (3/5) days

3. P, Q and R can do a work in 20, 30 and 60 days respectively. How many days does it need to complete the work if P does the work and he is assisted by Q and R on every third day?
A. 10 days	B. 14 days
C. 15 days	D. 9 days

Answer : Option C

Explanation :

Amount of work P can do in 1 day = 1/20

Amount of work Q can do in 1 day = 1/30

Amount of work R can do in 1 day = 1/60

P is working alone and every third day Q and R is helping him

Work completed in every three days = 2 × (1/20) + (1/20 + 1/30 + 1/60) = 1/5

So work completed in 15 days = 5 × 1/5 = 1

Ie, the work will be done in 15 days

H.C.F. and L.C.M.

1. Two numbers are in the ratio 2 : 3. If their L.C.M. is 48. what is sum of the numbers?
A. 28	B. 40
C. 64	D. 42

Answer : Option B

Explanation :

Let the numbers be 2x and 3x

LCM of 2x and 3x = 6x (∵ LCM of 2 and 3 is 6. Hence LCM

of 2x and 3x is 6x)

Given that LCM of 2x and 3x is 48

=> 6x = 48

=> x = ⁴⁸⁄₆ = 8

Sum of the numbers = 2x + 3x = 5x = 5 × 8 = 40

2. What is the greatest number of four digits which is divisible by 15, 25, 40 and 75 ?
A. 9800	B. 9600
C. 9400	D. 9200

Answer : Option B

Explanation :

Greatest number of four digits = 9999

LCM of 15, 25, 40 and 75 = 600

9999 ÷ 600 = 16, remainder = 399

Hence, greatest number of four digits which is divisible by 15, 25, 40 and 75

= 9999 - 399 = 9600

3. Three numbers are in the ratio of 2 : 3 : 4 and their L.C.M. is 240. Their H.C.F. is:
A. 40	B. 30
C. 20	D. 10

Answer : Option C

Explanation :

Let the numbers be 2x, 3x and 4x

LCM of 2x, 3x and 4x = 12x

=> 12x = 240

=> x = ²⁴⁰⁄₁₂ = 20

H.C.F of 2x, 3x and 4x = x = 20

Problems on Trains

1. A train is running at a speed of 40 km/hr and it crosses a post in 18 seconds. What is the length of the train?
A. 190 metres	B. 160 metres
C. 200 metres	D. 120 metres

Answer : Option C

Explanation :

Speed of the train, v = 40 km/hr = 40000/3600 m/s = 400/36 m/s

Time taken to cross, t = 18 s

Distance Covered, d = vt = (400/36)× 18 = 200 m

Distance covered is equal to the length of the train = 200 m

2. A train ,130 meters long travels at a speed of 45 km/hr crosses a bridge in 30 seconds. The length of the bridge is
A. 270 m	B. 245 m
C. 235 m	D. 220 m

Answer : Option B

Explanation :

Assume the length of the bridge = x meter

Total distance covered = 130+x meter

total time taken = 30s

speed = Total distance covered /total time taken = (130+x)/30 m/s

=> 45 × (10/36) = (130+x)/30

=> 45 × 10 × 30 /36 = 130+x

=> 45 × 10 × 10 / 12 = 130+x

=> 15 × 10 × 10 / 4 = 130+x

=> 15 × 25 = 130+x = 375

=> x = 375-130 =245

3. A train has a length of 150 meters . it is passing a man who is moving at 2 km/hr in the same direction of the train, in 3 seconds. Find out the speed of the train.
A. 182 km/hr	B. 180 km/hr
C. 152 km/hr	D. 169 km/hr

Answer : Option A

Explanation :

Length of the train, l = 150m

Speed of the man , Vm= 2 km/hr

Relative speed, Vr = total distance/time = (150/3) m/s = (150/3) × (18/5) = 180 km/hr

Relative Speed = Speed of train, Vt - Speed of man (As both are moving in the same direction)

=> 180 = Vt - 2

=> Vt = 180 + 2 = 182 km/hr

Boats and Streams

1. A man's speed with the current is 15 km/hr and the speed of the current is 2.5 km/hr. The man's speed against the current is:
A. 8.5 km/hr	B. 10 km/hr.
C. 12.5 km/hr	D. 9 km/hr

Answer : Option B

Explanation :

Man's speed with the current = 15 km/hr

=>speed of the man + speed of the current = 15 km/hr

speed of the current is 2.5 km/hr

Hence, speed of the man = 15 - 2.5 = 12.5 km/hr

man's speed against the current = speed of the man - speed of the current

= 12.5 - 2.5 = 10 km/hr

2. A motorboat, whose speed in 15 km/hr in still water goes 30 km downstream and comes back in a total of 4 hours 30 minutes. The speed of the stream (in km/hr) is:
A. 10	B. 6
C. 5	D. 4

Answer : Option C

Time taken downstream = 30(15+v)

Time taken upstream = 30(15−v)

total time = 30(15+v)+30(15−v)

It is given that total time is 4 hours 30 minutes = 412 hour 
                                                                 = 92 houri.e., 30(15+v)+30(15−v)=92
⇒1(15+v)+1(15−v)=92×30=320

⇒15−v+15+v(15+v)(15−v)=320

⇒30152−v2=320⇒30225−v2=320

⇒10225−v2=120⇒225−v2=200

⇒v2=225−200=25

⇒v=5 km/hr