PARTNERSHIP PROBLEMS

1. Three partners, A,B,C invest Rs.36000, Rs45000, Rs.54000 respectively. In a business . Out of a total profit of Rs.37500, c’s share is.
Ans: 15000

2. Kavitha and Sunitha are partners in a business. Kavita invests Rs.35000 for 8 months and Sunitha invests Rs.42000 for 10 months. Out of a profit of Rs.31570, Kavita’s share is
ans :Rs.12628

3. Jayant opened a shop investing Rs.30000, Madhu joined him 2 months lates investing Rs.45000. They earned a profit of Rs.54000 after completion of one year. What will be Madhu’s share of profit?
Ans: 30000

4. Nirmal and Kapil started a business investing Rs.9000 and Rs.12000 respectively. After 6 months, kapil withdrew half of his investment. If after a years, the total profit was Rs.4600, what was kapils share in it ?
Ans Rs.2300

5. A,B and C enter into a partnership. A initially invests Rs.25 laksh and adds another Rs.10lakhs after one year. B initially invests Rs.35 laksh and withdraws Rs.10laksh after 2 years and C invests Rs.30 laksh. In what ratio should the profits be divided at the end of 3 years?
Ans: 19:19:18

6. Mohinder and Surinder entered into a partnership investing Rs.12000 and Rs.9000 rep. After 3 months sudhir joined them with an investment of Rs.15000. What is the share of Sudhir in a halfyearly profit of Rs.9500?
ans Rs.2500

Ratios and Proportions

1) Find the ratio between 6 dollars to 25 cents
A) 25:2
B) 24:5
C) 24:1
D) 25:10

2) What is the compounded ratio of (5 : 3),(6 : 5) and (11 : 3)
A) 22:3
B) 11.:5
C) 10:6
D) 17:12

3) Find out the third proportion to 0.27 to 0.45?
A) 0.75
B) 1
C) 2
D) 3

4) The price of Computer and CD player are in the ratio 6:5. If the computer costs Rs. 5000 more than CD player.  What is the price of the computer?
A) 25,000
B) 15,000
C) 50,000
D) 30,000

5) If Rs. 582 be divided into three parts, proportional to 1/2:2/3:3/4, then the first part is?
A) 161
B) 151.8
C) 142
D) 153

TIME & DISTANCE APTI Q&A

1. Excluding stoppages, the speed of a bus is 54 kmph and including stoppages, it is 45 kmph. For how many minutes does the bus stop per hour?
[A] 9
[B] 10
[C] 12
[D] 20

Explanation:
Due to stoppages, it covers 9 km less.
Time taken to cover 9 km = [(9/54)*60 min = 10 min.

2. The average speed of a train in the onward journey is 25% more than that in the return journey. The train halts for one hour on reaching the destination. The total time taken for the complete to and from journey is 17 hours, covering a distance of 800 km. The speed of the train in the onward journey is:
[A] 45 km/hr
[B] 47.5 km/hr
[C] 52 km/hr
[D] 56.25 km/hr

Explanation:
Let the speed in return journey be x km/hr.
Then, speed in onward journey =(125/100)x = (5/4)x km/hr
So. Speed in onward journey = [(5/4)*45] km/hr = 56.25 km/hr

3. Walking (6/7) th of his usual speed, a man is 12 minutes too late. The usual time taken by him to cover that distance is:
[A] 1 hour
[B] 1 hr 12 min
[C] 1 hr 15 min
[D] 1 hr 20 min

Explanation:
New speed = (6/7)of usual speed.
New time = (7/6) of usual time.
Therefore (7/6 of usual time)- (usual time) = (1/5) hr.
=> (1/6 of usual time)= (1/5) hr => usual time = (6/5) hr = 1 hr 12 min.

4. Three persons are walking from a place A to another place B. Their speeds are in the ratio of 4 : 3 : 5. The time ratio to reach B by these persons will be :

[A] 4 : 3 : 5
[B] 5 : 3 : 4
[C] 15 : 9 : 20
[D] 15 : 20 : 12

Explanation:
Ratio of speeds = 4 : 3 : 5
Therefore Ratio of times taken = (1/4) : (1/3) : (1/5) = 15 : 20 : 12

5. A motor car starts with the speed of 70 km/hr with its speed increasing every two hours by 10 kmph. In how many hours will it cover 345 kms?
[A] 2 (1/4) hrs
[E] None of these
[C] 4(1/2) hrs
[B] 4 hrs 5 min
[D] Can not be determined

Explanation:
Distance covered in first 2 hours = (70 x 2) km = 140 km
Distance covered in next 2 hours = (80 x 2) km = 160 km
Remaining distance = 345 – (140 + 160) = 45 km.
Speed in the fifth hour = 90 km/hr
Time taken to cover 45 km =(45/90) hr = (1/2) hr
Therefore Total time taken = 2 + 2 + (1/2) = 4 (1/2)hrs

Time and work – Aptitude problems and answers

1) X and Y can do a piece of work in 18 days. Y and Z together can do it in 24 days. if X is 2 times as good a work guy as Z, find in what time Y alone can do it.

A) 10 days
B) 36 days
C) 26 days
D) 30 days

2) X,Y,Z together can complete a work in 24 days, X and Z together can do 2 times as much as Y does. Also, X and Y can do 3 times as much as Z does. Find the time taken by each one to complete the work.
A) 72 days
B) 50 days
C) 65 days
D) 44 days

3) X does half as much work as Y in (1/3)rd of the time. If together they take 20 days to finish a job, how much days shall Y take to do it?
A) 31 days
B) 45 days
C) 50 days
D) 67 days

4) X,Y and Z together can earn money Rs.270 per day while X and Z together earn money Rs.115 and Y and Z together can earn money Rs.167. What is the daily earnings of Z?
A) Rs.12
B) Rs.16
C) Rs.10
D) Rs.20

5) If 6 guys or 12 girls can do a piece of work in 21 days. Then in how many days 5 guys and 8 girls will do the same work?
A) 7 days
B) 10 days
C) 1 day
D) 14 days

Aptitude Problems On Trains

1) What is the speed of the train whose length is 210 metres?

I. The train crosses another train (Howrah Express/12869) of 300 metres length running in opposite direction in 10 seconds.

II. The train crosses another train (Howrah Express/12869) running in the same direction at the speed of 60 km/hr in 30 seconds.

Explanation:

Time taken to cross the train, running in opposite directions = [(l1 + l2)/ (u + v)] sec.

=> 10 = [ (210 + 300)/ (u + v) ]

=>u + v = 51.

Time taken to cross the train, running in same direction = [ (l1 + l2)/(u - v)] sec.

=> 30 =[ (210 + 300)/ (u - 60 x (5/18)) ]

=> u = [ ( 17 +(50/3) ] m/sec.

Thus, u and v can be obtained.

2) What is the length of a running train crossing another 180 metre long train running in the

opposite direction?

I. The relative speed of the two trains was 150 kmph.

II. The trains took 9 seconds to cross each other.

Explanation:

Let the two trains of length a metres and b metres be moving in opposite directions at u m/s

and v m/s.

Time taken to cross each other = [ (a + b)/ (u + v) ] sec.

Now, b = 180, u + v = [ 150 x (5/18) ] m/sec = (125/3 ) m/sec.

=> 9 = [ (a + 180)/ (125/3) ]

=> a = (375 - 180) = 195 m.

3) What is the length of a running train?

I. The train crosses a man in 9 seconds.

II. The train crosses a 240 metre long platform in 24 seconds.

Explanation:

Time taken by train to cross a min = ( Length of train/ Speed of train )=> Speed

= (l/9)....(i)

Time taken by train to cross a platform =[ (Length of train +Length of platform)/ Speed of

train ] =>Speed = (l + 240)/24 ....(ii)

From (i) and (ii), we get l/9 = [ (l + 240)/24 ].