Partnership Quiz

1.A, B and C jointly start a business venture with a agreement that A would invest Rs. 13,000 for 6 months, B, Rs. 16,800 for 5 months and C, Rs. 20,000 for 3 months. A wants to be the working member for which he was to receive 5% of the profits. The profit earned was Rs. 14800 Calculate the share of B in the profit?
Rs 6000 Rs 5320 Rs 7800 Rs 5840

Explanation – For managing, A receives = 5% of Rs. 14800 = Rs. 740. Balance = Rs. (14800 – 740) = Rs. 14060 Ratio of their investments = (13000 x 6) : (16,800 x 5) : (20000 x 3) = 78000 : 84000 : 60000 = 13 : 14 : 10 B’s share = Rs.14060 x 14/37 = 5320

 2.Anuj, kamlesh and Vinni invested Rs. 16000, Rs. 8000 and Rs. 16000 respectively to open a business. Anuj left after 6 months. If after 8 months, there was a gain of Rs. 8010, then What will be the share of kamalesh?
1780 1635 1680 1800

Explanation – Anuj : Kamalesh : Vinni = (16000 x 6) : (8000 x 8) : (16000 x 8) = 48 : 32 : 64 = 3 : 2 : 4. Kamal’s share = Rs.8010 x 2/9 = Rs. 1780.

 3.A and B start a business with investments of Rs. 10000 and Rs. 9000 respectively. After 4 months, A takes out 1/2 of his capital. After 2 more months, B takes out 1/3 of his capital while C joins them with a capital of Rs. 14000. At the end of a year, they earn a profit of Rs. 10160. Find the share of each member in the profit?
Rs A – Rs. 3300, B – Rs. 3500, C – Rs. 3360 Rs A – Rs. 3200, B – Rs. 3600, C – Rs. 3360 Rs A – Rs. 3200, B – Rs. 3700, C – Rs. 3260 Rs A – Rs. 3200, B – Rs. 3500, C – Rs. 3460

Explanation – A : B : C = (10,000 x 4 + 5000 x 8) : (9000 x 6 + 6000 x 6) : (14000 x 6) = 80000 : 90000 : 84000 = 40 : 45 : 42 A’s share = Rs. 10160 x 40/127 = Rs. 3200; B’s share = Rs. 10160 x 45/127 = Rs. 3600; C’s share = Rs. 10160 x 42/127 = Rs. 3360.

 4.Anaya, Bela and Cendrella enter into a partnership Bussiness with Anaya’s contribution Rs. 20,000. If out of a total profit of Rs. 2000, Anaya gets Rs.100 and Bela gets Rs. 600, cendrella gets rs 400 then Cendrella’s capital is:
Rs 8000 Rs 8500 Rs 7000 Rs 6500

Explanation – A : B : C = 1000 : 600 : 400 = 5 : 3 : 2. Let their capitals be 5x, 3x, 2x respectively. Then, 5x = 20000 x = 4000. C’s capital = 2x = Rs. 8000.

 5.Riya and sima invested in a partnership business. Riya invests Rs. 70,000 for 8months and sima invests Rs. 84,000 for 10 months. Out of a profit of Rs. 63140, Riya’s share is:
Rs 25000 Rs 25256 Rs 24500 Rs 25270

Explanation – Ratio of their shares = (70000 x 8) : (84000 x 10) = 2 : 3. Reena’s share = Rs.63140 x 2/5 = Rs. 25256

Averages

1.A cricketer has completed 10 innings and his average is 21.5 runs. How many runs must he make in his next innings so as to raise his average to 24?
44 45 49 48

Explanation – Total of 10 innings = 21.5 x 10 = 215 Suppose he needs a score of a in 11th innings; then average in 11 innings = (215 + a) / 11= 24 or, a = 264-215 = 49

 2.1/3 rd of certain journey is covered at the rate of 25 km/hr, 1/4 th at the rate of 30 km/hr and rest at 50 km/hr. Find the averae speed for the whole journey?
31 1/3 km/hr 30 1/3 km/hr 33 1/3 km/hr 34 1/3 km/hr

Explanation – Let the journey by a km. Then a/3 km at the speed of 25 km/hr and a/4 km at 30 km/hr and the rest distance ( a- a/3 –a/4 ) = 5/12 x a at the speed of 50 km/hr. Total time taken during the journey of a km

 3.The average of six numbers is 3.95. The average of two of them is 3.4, while the average of the other two is 3.85. What is the average of the remaining two numbers?
4.2 4.6 5.1 5.6

Explanation – Sum of the remaining two numbers = (3.95 x 6) – [(3.4 x 2) + (3.85 x 2)] = 23.70 – (6.8 + 7.7) = 23.70 – 14.5 = 9.20 Average = 9.2/2 = 4.6

 4.The average salary of the entire staff in a office is Rs 120 per month. The average salary of officers is Rs 460 and that of non officer is Rs 110. If the number of officer is 15, then find the number of non-officer in the office?
450 550 510 520

Explanation – Let the required number of non-officers = a Then, 110a + 460 x 15 = 120 (15 + a) or, 120a – 110a = 450 x 15 – 120 x 15 = 15 (460 – 120) or, 10a = 15 x 340; a = 15 x 34 = 510

 5.Find the average of first 20 multiple of 7?
71.5 73.5 75.2 76.6

Explanation – Average = 7 (1+2+3+…….+20)/ 20= 7 x 20 x 21/ 20×2= 73.5

Data Sufficiency

In the following questions each question is followed by three statements I, II and III. Read the question and the statements carefully and choose your answer according to which set of statement(s) is/are sufficient to answer the question.
 1.What is the distance between city P and city Q?
 I.Two persons A and B started simultaneously from P to Q, with their speeds in the ratio 4 : 5
II.B reached P one hour earlier than A to Q.
III.The difference between speeds of A and B is 20 kmph
I and III only II and III only I and II only All I, II and III together

2.What is the rate of interest on a certain sum?
 I.The interest earned on the sum at the same rate of simple interest after 3 years is Rs.4500.
II.If the rate of interest is 2.5% more, the simple interest earned will be Rs.900 more.
 III.The amount received on the sum at the end of the 2 years at simple interest is Rs.15,000
I and II only II and III only All I, II and III together Any two statements together

3.What is the area of the rectangle?
 I.The ratio of length to breadth of the rectangle is 35 : 12.
II.The perimeter of the rectangle is 188 cm.
III.The length of diagonal of the rectangle is 74 cm
I and II only I and III only (I and II) or (II and III) Any two of the three

4.How many boys are there in the class?
I.The number of boys is 15 more than the number of girls.
 II.The average weight of boys is 41 kg and that of girls is 32 kg.
III.The average weight of all the students of the class is 37 kg
I and II only II and III only All I, II and III (I and II) or (II and III)

5.What is the profit percentage if a discount of 10% is offered on an article?
 I.Had there been no discount offered, the profit earned on the sale the article would be 40%.
 II.The discount offered on the article is 14% of the cost price.
III.The cost price of the article is Rs.1000
I only Either I or II All I, II & III together Each statement alone is sufficient

Time and Distance – Boats

1. If Nishu can swim downstream at 6kmph and upstream at 2kmph.What is his speed in still water ?
5 km/hr 4 km/hr 8 km/hr 7 km/hr

If the speed downloadstream is a km/ hr and the speed upstream is b km/ hr then Speed in still water is = ½ (a+b) km / hr [memory tool last 2 L cross and make +] Explanation: Given : speed downstream a = 6 km ph Speed upstream b = 2kmph Speed in still water = ½ (a+b) kmph = ½ (6+2) = 8/2 = 4kmph speed in still water = 4kmph

 2.Ashok can row upstream at 8kmph and downstream at 12kmph.What is the speed of the stream ?
6 km/hr 3 km/hr 2 km/hr 4 km/hr

Basic Formula: If the speed downstream is a kmph and the speed upstream is b kmph then Speed of the stream = ½ (a-b) kmph Explanation: Speed downstream a = 12kmph Speed upstream b = 8 kmph Speed of the stream = ½ (a-b) = ½ (12-8) = 4/2 = 2 kmph speed of the stream = 2kmph

 3.A man rows 750m in 775 seconds against the stream and returns in 7 1/2 minutes. What is rowing speed in still water ?
4.7km/hr 4 km/hr 3.5km/hr 6 km/hr

Basic Formula: i) Speed in still water = ½ (a+b) kmph where ‘a’ is speed downstream and ‘b’ is speed upstream ii) a km / hr = a x 5/18 m /s iii) a m/sec = a x 18/5 km/hr Explanation: Speed upstream ‘b’ = 750m / 775 sec = 30/31 m/sec Speed downstream ‘a’ = 750 m/ (15/2)minutes [ 1min=60 sec] a = 750m/450 sec =5/3 m/sec speed in still water = ½ (a+b) = ½ (750/450 + 750/675 ) m /sec = ½ (750/450 + 750/675 ) x 18/5 km/hr = ½ (5/3 + 30/31) x 18/5 km/hr = 4.7 km/hr

 4.A man can row 9 (1/3) kmph in still water and finds that it takes him thrice as much time to row up than as to row down the same distance in the river. What is speed of the current ?
5km/hr 3(1/2) km/hr 4 (2/3) km/hr 8 (3/2)km/hr

Basic Formula: Speed of current = ½ (a-b) km/hr Explanation: Let man’s rate upstream be x km/hr. Then his rate downstream is 3 x km/hr Given: Speed in still water = 9 (1/3) = 28/3 km/hr i.e, ½ (a+b) = 28/3 km/hr ½ (x+3x) = 28/3 2x = 28/3 x = 28/ 2 x 3 = 14/3 km/hr rate upstream b = 14/3 km/hr and rate downstream a = 14/3 x 3 = 14 km/hr speed of the current = ½ (a-b) = ½ (14 – 14/3) = ½ (42-14/3) = 28/6 = 4 (2/3) km/hr

 5.Sham can row a boat at 10kmph in still water. IF the speed of the stream is 6kmph, the time taken to row a distance of 80km down the stream is
4 hours 5 hours 3 hours 2 hours

Basic Formula: Speed of stream = ½ (a-b) km/hr Speed in still water = ½ (a+b) km/hr Explanation: Given: Speed in still water, ½ (a+b) = 10 km/hr a+b = 20 km/hr…………….(1) speed of the stream, ½ (a-b) = 6km/hr a-b = 12 km/hr …………….(2) (1)+(2 ) we get 2a = 32 a = 16 km/hr speed downstream =distance traveled / time taken time taken = 80/16 = 5 hours

Profit and Loss

1.A trader buys two articles at the same price. He sold one article at 20% profit and sold the other at 10% loss . Find his overall profit/loss percentage
10% loss 10% profit 5% loss 5% Profit

2.If a book is sold at 20% more than its usual price, an extra profit of Rs.120 would be made on it. find its usual selling price.
Rs.500 Rs.600 Rs.750 Rs.800

3.The loss made by selling 20 m of a cloth equals the cost price of 5 m of that cloth. Find the loss percentage
33 1/3% 25% 20% 40%

4.The profit made by selling 30 m of a cloth equals the cost price of 6 m of that cloth. find the profit percentage
25% 20% 16 2/3% 30%

5.The profit made by selling 25 m of a cloth equals the selling price of 5 m of that cloth. find the profit percentage?
25% 20% 16 2/3% 30%

Time and Distance – Trains

1. Two trains are moving in opposite directions at 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is:
58 sec 50 sec 48 sec 56 sec


A 270 m long train running at the speed of 120 kmph crosses another train running in opposite direction at the speed of 80 kmph in 9 seconds. What is the length of the other train?
180 230 245 235


Two trains of equal length are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. The faster train passes the slower train in 36 seconds. The length of each train is:
40 50 65 55


A train 125 m long passes a man, running at 5 kmph in the same direction in which the train is going, in 10 seconds. The speed of the train is:
35 km/hr 55 km/hr 48 km/hr 50 km/hr


A train travelling at a speed of 75 mph enters a tunnel 7/2 miles long. The train is 1/4 mile long. How long does it take for the train to pass through the tunnel from the moment the front enters to the moment the rear emerges?
1 min 3 min 5 min 6 min

Time and Distance

1.Nishu is standing on a railway bridge which is 180 m long. He finds that a train crosses the bridge in 20 seconds but himself in 8 seconds. Find the speed of the train?
A.35 kmph
B.54 kmph
C.62 kmph
D.70 kmph
E.None of these
Answer – B (54 kmph) 
Explanation – Let the length of the train be x metres.
Then, the train covers x metres in 8 seconds (train is actually covering itself because length of man is very less compartable to train)and (x + 180) metres in 20 seconds.
equate speed in both case,s=d/t
∴ x/8 =( x + 180) / 20 ⇔ 20x = 8(x + 180) ⇔ x = 120.
∴ Length of the train = 120 m.
Speed of the train = [120/8]m/sec (convert to km/hr i.e x 18/5)
=[120/8] x 18/5kmph = 54 kmph.

2.Two trains are running at 40 km/hr and 20 km/hr respectively in the same direction. Fast train completely passes a man sitting in the slower train in 5 seconds. What is the length of the fast train?
A.27 7/9 m
B.28 m
C.29 m
D.30 2/7 m
E.None of these
Answer – A (27 7/9 m) 
Explanation – When SAME direction- MINUS
Relative speed = (40-20) km/hr = [20 x 5/18] m/sec = [50/9] m/sec.
Length of faster train = sxt=[50/9 x 5] m = 250/9 m = 27 7/9 m.

3.Two train travel in opposite directions at 36 kmph and 45 kmph and a man sitting in slower train passes the faster train in 8 seconds. Then length of the faster train is:
A.120 m
B.140 m
C.160 m
D.180 m
E.None of these
Answer – D (180 m) 
Explanation – When OPP. direction-PLUS
Relative speed = (36 + 45) km/hr
= [81 x 5/18] m/sec = [45/2] m/sec.
Length of train = [45/2 x 8] m = 180 m.

Time And Work

1.P and Q together can complete a work in 6 days. Q and R together can complete the same work in 15 days. P and R together can complete the work in 20/3 days. What is the ratio of number of days that Q alone takes to complete the work to the number of days that R alone takes to complete the work?
1 : 3 : 5
2 : 1 : 4
3 : 2 : 5
4 : 2 : 3
5 : None of these
2.A and B together can complete a piece of work in 15 days, B and C together can complete the work in 20 days. A and C together can complete the work in 30 days. What is the ratio of number of days A alone takes to do the work to the number of days C alone takes to do the work?
1 : 1 : 6
2 : 1 : 3
3 : 2 : 3
4 : 3 : 2
5 : None of these
3.Two boys can do a piece of work in ten days. Three girls can do the same work in five days. In how many days can a boy and a girl together do the work?
1 : 16 days
2 : 8(4/7) days
3 : 12 days
4 : 5 (1/2)days
5 : None of these
4.Four men can complete a work in 5 days which 20 women take 20 days to complete. How many days will 6 men and 40 women together take to complete the work?
1 : 1day
2 : 4days
3 : 2 (1/2)days
4 : 3days
5 : None of these
5.A and B can complete a work in 20 days and 30 days respectively. Both of them started doing the work and A left after six days. In how many more days can B complete the remaining work?
1 : 20
2 : 10
3 : 15
4 : 12
5 : None of these